题目描述
输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则。
struct ListNode {
int val;
struct ListNode *next;
ListNode(int x) :
val(x), next(NULL) {
}
};
class Solution {
public:
ListNode* Merge(ListNode* pHead1, ListNode* pHead2)
{
ListNode *head;
if(pHead1==NULL&&pHead2==NULL) return head;
if(pHead1==NULL) return pHead2;
if(pHead2==NULL) return pHead1;
if(pHead1->val<pHead2->val){
head=new ListNode(pHead1->val);
pHead1=pHead1->next;
}else{
head=new ListNode(pHead2->val);
pHead2=pHead2->next;
}
ListNode *p=head;
while(pHead1!=NULL||pHead2!=NULL){
ListNode *t;
if(pHead1!=NULL&&pHead2!=NULL){
if(pHead1->val<pHead2->val){
t=new ListNode(pHead1->val);
pHead1=pHead1->next;
}else{
t=new ListNode(pHead2->val);
pHead2=pHead2->next;
}
}else if(pHead1!=NULL&&pHead2==NULL){
t=new ListNode(pHead1->val);
pHead1=pHead1->next;
}else if(pHead1==NULL&&pHead2!=NULL){
t=new ListNode(pHead2->val);
pHead2=pHead2->next;
}
p->next=t;
p=t;
}
return head;
}
};